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PowerApps Submit data to data source


The SubmitForm function in PowerApps is used to submit a form's data to the underlying data source. This function triggers the form's OnSuccess and OnFailure properties, allowing you to handle what happens after the submission is processed.

PowerApps – SubmitForm() function Syntax

SubmitForm(FormName)

  • FormName: The name of the form control that you want to submit.

Notes:

  • Form Validation: Ensure that the form validation rules are set up correctly so that users provide all necessary information before submission.
  • Error Handling: Properly handle errors and provide meaningful feedback to users in the OnFailure property.

PowerApps - Basic Form Submission

Suppose you have a form named EditForm1 and a button that submits this form:

SubmitForm(EditForm1)

Set this code in the OnSelect property of the button to submit the form data when the button is clicked.

PowerApps – Notify after successful form submission

To handle successful submission, set the OnSuccess property of the form. For example, navigate to a different screen or display a success message:

// OnSuccess property of EditForm1

Notify("Form submitted successfully!", NotificationType.Success);

Navigate(SuccessScreen, ScreenTransition.Fade)

PowerApps – Notify using message after Form submission failed

To handle submission failure, set the OnFailure property of the form. For example, display an error message:

// OnFailure property of EditForm1

Notify("Failed to submit the form. Please try again.", NotificationType.Error)

PowerApps – Handle Data Entry Form submission response

Suppose you have a data entry form for submitting new records to a Products table. You can use a button to submit the form and handle the outcome:

// OnSelect property of the submit button

SubmitForm(ProductForm)

 

 

// OnSuccess property of ProductForm

Notify("Product added successfully!", NotificationType.Success);

ResetForm(ProductForm);

Navigate(ProductListScreen, ScreenTransition.Fade)

 

 

// OnFailure property of ProductForm

Notify("Failed to add product. Please check your input and try again.", NotificationType.Error)

 


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